Integrand size = 26, antiderivative size = 117 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=-\frac {16 i (a+i a \tan (c+d x))^{13/2}}{13 a^4 d}+\frac {8 i (a+i a \tan (c+d x))^{15/2}}{5 a^5 d}-\frac {12 i (a+i a \tan (c+d x))^{17/2}}{17 a^6 d}+\frac {2 i (a+i a \tan (c+d x))^{19/2}}{19 a^7 d} \]
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Time = 0.12 (sec) , antiderivative size = 117, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {3568, 45} \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=\frac {2 i (a+i a \tan (c+d x))^{19/2}}{19 a^7 d}-\frac {12 i (a+i a \tan (c+d x))^{17/2}}{17 a^6 d}+\frac {8 i (a+i a \tan (c+d x))^{15/2}}{5 a^5 d}-\frac {16 i (a+i a \tan (c+d x))^{13/2}}{13 a^4 d} \]
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Rule 45
Rule 3568
Rubi steps \begin{align*} \text {integral}& = -\frac {i \text {Subst}\left (\int (a-x)^3 (a+x)^{11/2} \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {i \text {Subst}\left (\int \left (8 a^3 (a+x)^{11/2}-12 a^2 (a+x)^{13/2}+6 a (a+x)^{15/2}-(a+x)^{17/2}\right ) \, dx,x,i a \tan (c+d x)\right )}{a^7 d} \\ & = -\frac {16 i (a+i a \tan (c+d x))^{13/2}}{13 a^4 d}+\frac {8 i (a+i a \tan (c+d x))^{15/2}}{5 a^5 d}-\frac {12 i (a+i a \tan (c+d x))^{17/2}}{17 a^6 d}+\frac {2 i (a+i a \tan (c+d x))^{19/2}}{19 a^7 d} \\ \end{align*}
Time = 0.52 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.62 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=-\frac {2 a^2 (-i+\tan (c+d x))^6 \sqrt {a+i a \tan (c+d x)} \left (-2429 i-5291 \tan (c+d x)+4095 i \tan ^2(c+d x)+1105 \tan ^3(c+d x)\right )}{20995 d} \]
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Time = 1.92 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.70
\[\frac {2 i \left (\frac {\left (a +i a \tan \left (d x +c \right )\right )^{\frac {19}{2}}}{19}-\frac {6 a \left (a +i a \tan \left (d x +c \right )\right )^{\frac {17}{2}}}{17}+\frac {4 a^{2} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {15}{2}}}{5}-\frac {8 a^{3} \left (a +i a \tan \left (d x +c \right )\right )^{\frac {13}{2}}}{13}\right )}{d \,a^{7}}\]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 190 vs. \(2 (85) = 170\).
Time = 0.29 (sec) , antiderivative size = 190, normalized size of antiderivative = 1.62 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=-\frac {1024 \, \sqrt {2} {\left (16 i \, a^{2} e^{\left (19 i \, d x + 19 i \, c\right )} + 152 i \, a^{2} e^{\left (17 i \, d x + 17 i \, c\right )} + 646 i \, a^{2} e^{\left (15 i \, d x + 15 i \, c\right )} + 1615 i \, a^{2} e^{\left (13 i \, d x + 13 i \, c\right )}\right )} \sqrt {\frac {a}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}}}{20995 \, {\left (d e^{\left (18 i \, d x + 18 i \, c\right )} + 9 \, d e^{\left (16 i \, d x + 16 i \, c\right )} + 36 \, d e^{\left (14 i \, d x + 14 i \, c\right )} + 84 \, d e^{\left (12 i \, d x + 12 i \, c\right )} + 126 \, d e^{\left (10 i \, d x + 10 i \, c\right )} + 126 \, d e^{\left (8 i \, d x + 8 i \, c\right )} + 84 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 36 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 9 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \]
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Timed out. \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=\text {Timed out} \]
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none
Time = 0.22 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.65 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=\frac {2 i \, {\left (1105 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {19}{2}} - 7410 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {17}{2}} a + 16796 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {15}{2}} a^{2} - 12920 \, {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {13}{2}} a^{3}\right )}}{20995 \, a^{7} d} \]
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\[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{\frac {5}{2}} \sec \left (d x + c\right )^{8} \,d x } \]
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Time = 16.99 (sec) , antiderivative size = 626, normalized size of antiderivative = 5.35 \[ \int \sec ^8(c+d x) (a+i a \tan (c+d x))^{5/2} \, dx=-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,16384{}\mathrm {i}}{20995\,d}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,8192{}\mathrm {i}}{20995\,d\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,6144{}\mathrm {i}}{20995\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^2}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,1024{}\mathrm {i}}{4199\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^3}+\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,536576{}\mathrm {i}}{4199\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^4}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,10484736{}\mathrm {i}}{20995\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^5}+\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,17262592{}\mathrm {i}}{20995\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^6}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,1129472{}\mathrm {i}}{1615\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^7}+\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,98304{}\mathrm {i}}{323\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^8}-\frac {a^2\,\sqrt {a-\frac {a\,\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1}}\,1024{}\mathrm {i}}{19\,d\,{\left ({\mathrm {e}}^{c\,2{}\mathrm {i}+d\,x\,2{}\mathrm {i}}+1\right )}^9} \]
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